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Simplify the parser_t::eval() return type to void

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The return value was unused.
This commit is contained in:
ridiculousfish
2018-02-11 23:13:06 -08:00
parent 4eb73862fc
commit d536b152f7
2 changed files with 9 additions and 13 deletions
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18
src/parser.cpp
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@@ -644,22 +644,18 @@ int parser_t::eval(wcstring cmd, const io_chain_t &io, enum block_type_t block_t
fwprintf(stderr, L"%ls\n", backtrace_and_desc.c_str());
return 1;
}
return this->eval(ps, io, block_type);
this->eval(ps, io, block_type);
return 0;
}
int parser_t::eval(parsed_source_ref_t ps, const io_chain_t &io, enum block_type_t block_type) {
void parser_t::eval(parsed_source_ref_t ps, const io_chain_t &io, enum block_type_t block_type) {
CHECK_BLOCK(1);
assert(block_type == TOP || block_type == SUBST);
if (ps->tree.empty()) {
return 0;
if (!ps->tree.empty()) {
// Execute the first node.
tnode_t<grammar::job_list> start{&ps->tree, &ps->tree.front()};
this->eval_node(ps, start, io, block_type);
}
// Execute the first node.
tnode_t<grammar::job_list> start{&ps->tree, &ps->tree.front()};
this->eval_node(ps, start, io, block_type);
return 0;
}
template <typename T>